Three identical spheres each of mass M are placed at corners of right angle triangle with mutually perpendicular sides equal to 2m. Taking point of intersection of two mutually perpendicular sides as origin find position vector center of mass

Options

A. (##PW_NEET_45_DAY_PHY_C06_E03_004_Q01##)
B. `(2)/(3) (hati + hatj)`
C. `(4)/(3) (hati + hatj)`
D. `2(hati + hatj)`

Explanation

`X _("com") = ( M xx 0 + M zz 3 + M xx 0)/(3M)=2/3`
`Y _("com")= ( M xx 0 + M xx 2 + M xx 0 )/(3M) = (2)/(3)`
Position vector `(2)/(3) hati + (2)/(3) hatj = (2)/(3) (hati + hatj)`