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Two rotating bodies A and B of masses m ...

Two rotating bodies `A` and `B` of masses `m` and `2m` with moments of inertia `I_(A)` and `I_(B) (I_(B) gt I_(A))` have equal kinetic energy of rotation. If `L_(A)` and `L_(B)` be their angular momenta respectively, then

A

`L _(B) gt L _(A)`

B

`L _(A) gt L _(B) `

C

`L _(A) = (L _(B))/(2)`

D

`L _(A) = 2 L _(B)`

Text Solution

Verified by Experts

`K _(A) = K _(a ) implies (L _(A) ^(2))/(2I _(A))= (I _(B) ^(2))/( 2 I _(B))`
As `I _(B) gt I _(A) So, L _(A) ^(2) lt L _(B) ^(2) impliesL _(A) lt L _(B) implies L _(B) gt L _(A)`
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