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In a cyclic process shown in the figure ...

In a cyclic process shown in the figure an ideal gas is adiabatically taken from `B`to`A`, the work done on the gas during the process `B`to`A` is `30,J` when the gas is taken from `A` to `B` the heat absorbed by the gas is `20 J` Then change in internal energy of the gas in the process `A` to `B` is :

A

20J

B

`-30J`

C

50J

D

`-10J`

Text Solution

Verified by Experts

The correct Answer is:
B
`B to A`
`triangleQ=0`
`0=-30+triangleU_(BA)`
`triangleU=30J`
`triangleU_(BA)=30J`
`triangleU_(AB)=-triangleU_(BA)=-30J`
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