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Two strings of copper are stretched to t...

Two strings of copper are stretched to the same tension. If their cross-section area are in the ratio 1 : 4 , then the respective wave velocities will be

A

`4:1`

B

`2:1`

C

`1:2`

D

`1:4`

Text Solution

Verified by Experts

The correct Answer is:
B
`v = sqrt(T/(mu)) = sqrt(T/(rho A))`
where , `rho` = density,
A = Area of cross-section
`mu = mu A` = mass of unit length
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