If `lambda_(1), lambda_(2), lambda_(3)` are the wavelengths of the waves giving resonance in the fundamental, first and second overtone modes respecively in a open organ pipe, then the ratio of the wavelengths `lambda_(1) : lambda_(2) : lambda_(3)`, is :

Options

A. `1:2:3`
B. `1:3:5`
C. `1:1//2:1//3`
D. `1:1//3: 1//5`

Answer

C

Explanation

`n_1 : n_2 : n_3 = 1 : 2 : 3`
`V/(lambda_1) : V/(lambda_2) : V/(lambda_3) = 1 : 2 : 3`
`lambda_1 : lambda_2 : lambda_3 = 1 : 1/2 : 1/3`