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An engine driver moving towards a wall w...

An engine driver moving towards a wall with velocity of `50 ms^(-1)` emits a note of frequnecy `1.2 kHz`. The frequency of note after reflection from the wall as heard by the engine driver when speed of sound in air is `350 ms^(-1)` is :

A

`1 kHz`

B

`1.8 kHz`

C

`1.6 kHz`

D

`1.2 kHz`

Text Solution

Verified by Experts

The correct Answer is:
C
`n. = ((V + V_s)/(V - V_s))n`
` = (350 + 50)/(350 - 50) xx 1.2 KHz = 400/300 xx 1.2 KHz`
`= 1.5 KHz`
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