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In a ammeter 0.2% of main current passes...

In a ammeter `0.2%` of main current passes through the galvanometer. If resistance of galvanometer is `G`, the resistance of ammeter will be

A

`(1)/(499)G`

B

`(499)/(500)G`

C

`(1)/(500)G`

D

`(500)/(499)G`

Text Solution

Verified by Experts

The correct Answer is:
A
Parallel combination potential is same

`V_(g)=V_("shunt")`
`I_(g)G=I_("main")R_(eq)`
`(21G)/(1000)=(1GR)/(G+R)`
`500R =G+R`
`499R=G`
`R=(G)/(499)`
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