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A seriesLCR circuit is connected to an a...

A seriesLCR circuit is connected to an ac voltage source. When L is removed from the circuit, the phase difference between current and voltage is `pi/3`. If instead C is removed from the circuit phase difference is agin `pi/3` between current and voltage. Power factor of circuit is:

A

`0.5`

B

`1.0`

C

`-1.0`

D

Zero

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Knowledge Check

  • In an electrical circuit R,L, C and a.c voltage source are all connected in series. When L is removed from the circuit , the phase difference between the voltage and current in the circuit is π/6. If instead ,C is removed from the circuit , the phase difference is again π/6 . The power factor of the circuit is

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  • In an electrical circuit R,L,C and an AC voltage source are all connected in series. When L is removed from the circuit, the phase difference between the voltage and the current in the circuit is pi//3 . If instead, C is removed from the circuit, difference the phase difference is again pi//3 . The factor of the circuit is

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  • An Ac voltage V=V_0 sin 100t is applied to the circuit, the phase difference between current and voltage is found to be pi/4 , then .

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