A part of a circuit is shown in figure `V_(R)-V_(C )` is equal to 12 V. `I_(1)` is equal to

Options

A. 1A
B. 2A
C. 3A
D. 4A

Answer

C

Explanation

If `V_(B)-V_(C )=12` then potential drop across `2Omega` resistor between B & C is 2V so, current flow from B to C
`=(2)/(2) =1A`
By junction rule `I_(1)=3+1=3A`.