Home
Class 12
PHYSICS
A resistance wire connected in left gap ...

A resistance wire connected in left gap of a metre bridge balances a 10 ohm resistance in right gap at point which divides bridge wire in ratio 3:2. if length of resistance wire is 1.5 m then length of 1 ohm of resistance wire is

A

`1.0 xx 10^(-1)`m

B

`1.5xx10^(-1)`m

C

`1.5 xx 10^(-2)`m

D

`1.0xx10^(-2)m`

Text Solution

Verified by Experts

The correct Answer is:
A

`(R )/(10)=(l_(1))/(l_(2))=(R )/(10)=(3)/(2), R=15Omega`
length of `1Omega ` resistance wire `=(1.5)/(15)=0.1 =1xx10^(-1)m`.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    PHYSICS WALLAH|Exercise Level-2 |30 Videos

  • ALTERNATING CURRENT

    PHYSICS WALLAH|Exercise NEET PAST 5 YEARS QUESTIONS |8 Videos

  • DUAL NATURE OF RADIATION AND MATTER

    PHYSICS WALLAH|Exercise Neet past 5 years questions|16 Videos

Similar Questions

Explore conceptually related problems

A resistance of 5Omega is connected in one gap of a metre bridge and 15Omega in the other gap. Calculate the position of the balancing point.

An unknown resistance is connected in a left gap of a metre bridge . The balance point is obtained when a resistance of 10 Omega is taken out from the resistance box in the right gap. On increasing the resistance from the resistance box by 12.5 Omega the balance point shifts by 20 cm. find the unknown resistance.

Knowledge Check

  • A wire connected in the left gap of a meter bridge balance a 10Omega resistance in the right gap to a point, which divides the bridge wire in the ratio 3:2. If the length of the wire is 1m. The length of one ohm wire is

    A
    0.057m
    B
    0.067m
    C
    0.37m
    D
    0.134m

  • A wire of length 3 m connected in the left gap of a metre bridge balances a 8 Omega resistance in the right gap at a point, which divides the bridge wire in the ratio of 3 :2 . What is the length of the wire corresponding to a resistance of the length of the wire corresponding to a resistance of 1 Omega ?

    A
    1m
    B
    0.75 m
    C
    0.5 m
    D
    0.25 m

  • Two equal resistance are connected in the gaps of a metre bridge. If the resistance in the left gap is increased by 10% the balancing point shift

    A
    `10%` to right
    B
    `10%` to left
    C
    `9.6%` to left
    D
    `4.8%` to right

    • Similar Questions

    Explore conceptually related problems

    A 6Omega resistance is connected in the left gap of a meter bridge.In the second gap 3Omega and 6Omega are joined in parallel.The balance point of the bridge is at

    When two known resistance R and S are connected in the left and right gaps of a meter bridge, the balance point is found at a distance l_(1) from the zero end of the meter bridge wire. An unknown resistance X is now connected in parallel to the resistance S and the balance point is found at a distance l_(2) from the zero end of the meter bridge wire, Obtain a formula for X in terms of l_(1), l_(2) and S.

    Two equal resistance are connected in the gaps of a metre bridge. If the resistance in the left gap is increased by 10\%, the balancing point shift

    A metre bridge is balanced with known resistance in the right gap and a metal wire in the left gap. If the metal wire is heated the balance point.

    In a metre bridge expt, when the resistances in the gaps are interchanged the balance point is increases by 10 cm. The ratio of the resistances is

    Home
    Profile