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For the circuit shown in the figure, the...

For the circuit shown in the figure, the current I will be

A

1A

B

1.5A

C

0.5A

D

0.75A

Text Solution

Verified by Experts

The correct Answer is:
A
`I=(E_(1)+E_(2))/(R_(1)+R_(2)+R_(3))=(2+4)/(4+1+1)=(6)/(6)=1` ampere
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