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A potentiometer wire is 100 cm long hand...

A potentiometer wire is `100 cm` long hand a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obatined at `50 cm` and `10 cm` from the positive end of the wire in the two cases. The ratio of emfs is:

A

`5:1`

B

`5:4`

C

`3:4`

D

`3:1`

Text Solution

Verified by Experts

The correct Answer is:
D
`(E_(1)+E_(2))/(E_(1)-E_(2))=(50)/(10)`
`(2E_(1))/(2E_(2))=(50+10)/(50-10)=(E_(1))/(E_(2))=(3)/(2)`
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