Home
Class 12
PHYSICS
A proton (mass = 1.67xx10^(-27) kg and c...

A proton `(mass = 1.67xx10^(-27) kg` and charge `1.6xx10^(-19) C)` enters perpendicular to a magentic field of intensity `2 weber//m^(2)` with a speed of `2.6xx10^(7) m//sec`. The acceleration of the proton should be

A

`6.5 xx 10^(15) m//sec^(2)`

B

`6.5 xx 10^(13) m//sec^(2)`

C

`6.5 xx 10^(11) m//sec^(2)`

D

`6.5 xx 10^(9) m//sec^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • MOVING CHARGES AND MAGNETISM

    PHYSICS WALLAH|Exercise LEVEL - 2|30 Videos
  • MOVING CHARGES AND MAGNETISM

    PHYSICS WALLAH|Exercise NEET PAST 5 YEARS QUESTIONS |12 Videos
  • MOTION IN A STRAIGHT LINE

    PHYSICS WALLAH|Exercise NEET Past 5 Years Questions|5 Videos
  • OSCILLATIONS

    PHYSICS WALLAH|Exercise NEET PAST 5 YEARS QUESTIONS |5 Videos

Similar Questions

Explore conceptually related problems

A proton of mass 1.67 xx 10^(-27) kg and charge 1.6 xx 10^(-19) C is shot a uniform magnetic field, and perpendicular to the field with a velocity 5 xx 10^(6) m//s . If the magnetic induction of the field is 1 tesla, find (i) The radius of the circular path

An electron (mass =9.0xx10^(-31) kg and charge =1.6xx10^(-19) coulomb) is moving in a circular orbit in a magnetic field of 1.0xx10^(-4)"weber"//m^(2) . Its perido of revolution is

A proton of mass 1.67 × 10^(-27) kg and charge 1.6 × 10^(-19) C is shot a uniform magnetic field, and perpendicular to the field with a velocity 5 × 10^(6) m//s . If the magnetic induction of the field is 1 tesla, find (ii) The frequency of revolution.

A proton enters a magnetic fiedl of flux density 1.5"weber"//m^(2) with a velocity of 2xx10^(-7)m//sec at an angle of 30^(@) with the field. The force on the proton will be

An alpha- particle of mass 6.65xx10^(-27) kg travels perpendicular to a magnetic of 0.2 T with a speed of 6xx10^(5)ms^(-1) . Calculate the acceleration of the alpha- particle. Given the charge on the electron is 1.6xx10^(-19)C .

A proton of mass 1.67xx10^(-27) kg charge 1.6xx10^(-19) C is projected in xy-plane with a speed of 2xx10^(6) m//s at an angle of 60^(@) to the X-axis. If a uniform magnetic field of 0.14 T is applies along the Y-axis, then the path of the proton is

A particle of mass 6.4xx10^(-27) kg and charge 3.2xx10^(-19)C is situated in a uniform electric field of 1.6xx10^5 Vm^(-1) . The velocity of the particle at the end of 2xx10^(-2) m path when it starts from rest is :