An electron is revolving round a proton, producing a magnetic field of `16 weber//m^(2)` in a circular orbit of radius `1 Å. Its angular velocity will be

Options

A. `10^(12)` rad/sec
B. `1//2 pi xx 10^(12)` rad/sec
C. `2 pi xx 10^(12)` rad/sec
D. `4 pi xx 10^(12)` rad/sec

Answer

A

Explanation

Magnetic field due to revolution of electron
`B = (mu_(0))/(4pi) xx (2 pi I)/(r) = (mu_(o))/(4 pi) xx (2pi)/(r) ((e omega)/(2 pi))`
`B = 10^(-7) xx (e omega)/(r)`
`16 = 10^(-7) xx (1.6 xx 10^(-19) xx omega)/(1 xx 10^(-10))`
`omega = 10^(17)` rad/sec