A long solenoid carrying a current prod...

A long solenoid carrying a current produces a magnetic field `B` along its axis. If the current is doubled and the number of turns per cm is halved, the new value of the magnetic field is

B/2

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The correct Answer is:

`B = mu_(o)ni`
`(B_(2))/(B_(1)) = (n_(2)l_(2))/(n_(2)l_(1)): n_(2) = (n_(1))/(2), i_(2) = 2i_(1)" "rArr" "B_(2) = B_(1) = B`

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