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Current i is carried in a wire of length...

Current `i` is carried in a wire of length `L`. If the wire is turned into a circular coil, the maximum magnitude of torque in a given magnetic field `B` will be

A

`(LIB^(2))/(2)`

B

`(LI^(2)B)/(2)`

C

`(L^(2)IB)/(2)`

D

`(L^(2)IB)/(4 pi)`

Text Solution

Verified by Experts

The correct Answer is:
D

`tau_(max) = NABI " "= 1 xx 1 xx (pi r^(2))B`
`[(2pi r = L),(r = (L)/(2pi))]`
`tau_(max) = pi I((L)/(2pi))^(2) B " "rArr" "tau_(max) = (L^(2) IB)/(4 pi)`
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