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An average induced emf of 0.20 V appears...

An average induced emf of 0.20 V appears in a coil when the current in it is changed from 5.0A in one direction to 5.0 A in the opposite direction in 0.2 sec.

A

`4 xx 10^(-3) H`

B

`2 xx 10^(-3) H`

C

`2sqrt(2) xx 10^(-3) H`

D

`3sqrt(3) xx 10^(-3)H`

Text Solution

Verified by Experts

The correct Answer is:
A
As we know,
`e = L (dI)/(dt) implies 0.20 = (L (5 - (-5)))/(0.20)`
`implies L = (0.20 xx 0.20)/(5 + 5) = 4 xx 10^(-3) H`
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