Home
Class 12
PHYSICS
r.m.s. value of current i=3+4 sin (omega...

r.m.s. value of current `i=3+4 sin (omega t+pi//3)` is:

A

5A

B

`sqrt17A`

C

`(5)/(sqrt2) A`

D

`(7)/(sqrt2) A`

Text Solution

Verified by Experts

`[( int_(0) ^(t) t ^(2) dt )/( T )] ^((1)/(2))`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ALTERNATING CURRENT

    PHYSICS WALLAH|Exercise NEET PAST 5 YEARS QUESTIONS |8 Videos

  • ALTERNATING CURRENT

    PHYSICS WALLAH|Exercise NEET PAST 5 YEARS QUESTIONS |8 Videos

  • CURRENT ELECTRICITY

    PHYSICS WALLAH|Exercise NEET Past 5 Years Questions|23 Videos

Similar Questions

Explore conceptually related problems

If the rins value of current i=3+4 sin (omega t+pi / 3) is x ampere, then find x^(2) .

Find the rms value of current i=I_(m)sin omegat from (i) t=0 "to" t=(pi)/(omega) (ii) t=(pi)/(2omega) "to" t=(3pi)/(2omega)

Knowledge Check

  • r.m.s. value of current i=3+4sin (omegat+pi//3) is

    A
    5A
    B
    `sqrt2A`
    C
    `(5)/(sqrt2A)`
    D
    `(7)/(sqrt2)A`

    • Similar Questions

    Explore conceptually related problems

    The average value of current i=I_(m) sin omega t from t=(pi)/(2 omega ) to t=(3 pi)/(2 omega) si how many times of (I_m) ?

    The r.m.s. value of I = I_(1) sin omega t + I_(2) cos omega t is

    The r.m.s. value of I = I_(1) sin omega t + I_(2) cos omega t is

    Find the rms value of current from t = 0 to t=(2pi)/omega if the current varies as i=I_(m)sin omegat .

    Find the rms value of current from t=0 to t= (2pi)/(omega) if the current avries as i=I_(m)sin omegat .

    The root mean square r.m.s.value of alternating current I=60sin100 pi t is

    The root mean square (r.m.s .) value of alternating current I=60sin100 pi(t) is

    Home
    Profile