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A sinusoidal ac current flows through a ...

A sinusoidal ac current flows through a resistor of resistance R . If the peak current is `I_(p)` , then the power dissipated is

A

`I _(P) ^(2) R cos theta `

B

`(1)/(2) I _(0) ^(2) R`

C

`(4)/(pi) I _(P) ^(2) R`

D

`(1)/(pi ^(2)) I _(P) ^(2) R`

Text Solution

Verified by Experts

`lt P gt = I _(rms) ^(2) R = ((I _(P))/( sqrt2)) ^(2) R = (I _(P) ^(2) R)/( 2)`
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