A coil of inductance 5.0 mH and negligib...

A coil of inductance 5.0 mH and negligible resistance is connected to an alternating voltage `V=10 sin (100t)`. The peak current in the circuit will be:

2 amp

1 amp

10 amp

20 amp

Text Solution

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`I _(omega ) = ( V_(0))/( omega L ) = (10)/(100 xx 5 xx 10 ^(-3))`

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