A ray of light is incident at an angle of `45^@` on one face of a rectangular glass slab of thickness `10 cm` and refractive index `1.5`. Calculate the lateral shift produced.

Options

A. 0.33 m
B. 0.45 cm
C. 0.033 m
D. 0.045 m

Answer

C

Explanation

Here `i = 45^@ , t = 10 cm = 0.1 m, mu = 1.5` lateral shift = ?
As `mu = (sin i_1)/(sin r_1)`
`therefore sin r_1 = (sin i_1)/(mu) = (sin 45^@)/(1.5)`
`sin r_1 = (0.707)/(1.5)`
`sin r_1 = (0.707)/(1.5)`
`r_1 = 28.14^@`
lateral shift = `(l sin (i_1 - r_1))/(cos r_1)`
Lateral shift = 0.033 m`