In a full wave junction diode rectifier, the input a.c. has r.m.s. value of 20 V. The transformer used is a step up transformer having primary and secondary turns ratio 1: 2. Calculate the d.c. voltade in the recitified output.

Options

A. 12V
B. 24V
C. 36V
D. 42V

Answer

C

Explanation

Input `Y_(max)=20V`
Peak value of input voltage `V_n=sqrt2 V_(max)`
`=sqrt2 times 20=28.28V`
Since the transformer is a set up transformer having transformer ratio 1:2 the maximum value of output voltage of the transformer applied diode will be
`V_n=2 times 28.28V`
`(2V_a)/pi implies =(2 times 2 times 28.28)/(22/7)=36V`