For the given combination of gates, if the logic states of inputs `A,B,C` are as follows `A=B=C=0` and `A=B=1,C=0` then the logic states of output `Y` are

Options

A. 0,0
B. 0,1
C. 1,0
D. 1,1

Answer

D

Explanation

The output D for the given combination
`D=(overline(A+B C))=overline((A+B))+overlineC`
IF A=B=C=0 then `D=overline(0+0)+overline0=overline0+overline0=1+1`
IF A=B=1, C=0 then D `=overline((1+1))+overline0=overline1+overline0=0+1`