The current transfer ratio `beta` of a transistor is 50. The input resistance of the transistor when used in common emitter mode is 1 kilo ohm. The peak value of the collector alternating current for an input peak voltage of 0.01 volt is

Options

A. `100 mu A`
B. 0.01mA
C. 0.25mA
D. `500 mu A`

Answer

D

Explanation

IN common emitter configuration of a transistor, input current is a base current. Input current
`i_a=(DeltaV_B)/R_B`
=`0.01/1000=10^-5 A`
Also current gain
`beta=(ic)/(i_B)`
`implies i_e =betai_B=50 times 10^-5 A`
`=500 times 10^-6 A=500 mu A`