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A light emitting diode (LED) has a volta...

A light emitting diode `(LED)` has a voltage drop of `2V` across it and passes a current of `10 mA`. When it operates with a `6V` battery through a limiting resistor `R`. The value of `R` is

A

`40k Omega`

B

`4 k Omega`

C

`200 Omega`

D

`400 Omega`

Text Solution

Verified by Experts

The correct Answer is:
D
`4=10 times 10^-3 times R`
`R=400 Omega`
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