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For a certain reaction log K (S^(-1))= 14- (1.25 xx 10^(4)K)/(T) Hence it can be said that The E_(a) for the reaction is
The equilibrium constant can be expressed in terms of partial pressure as well as concentration. What is the relation between K_p and K_c for the reaction, N_2(g)+O_2(g) gives 2NO(g)?
Unit of rate constant (k) of a reaction depends on the order of the reaction Value of 'k' of two reaction are given below. Find the order of each reaction k=3xx10^(-2)molL^(-1)s^(-1)
Unit of rate constant (k) of a reaction depends on the order pf the reaction Value of 'k' of two reaction are given below. Find the order of each reaction k=5xx10^(-3)molL^(-1)s^(-1)
The K_(c) of the hypothetical reaction P+Q iff R+S is 3 times 10^(-1) at 400 K and 2 times 10^(-2) at 500 K. From this data, one can infer that, for the reaction
Assertion : The equilibrium constant of an exothermic reaction decreases as temperature increases. Reason : log(K_(2)/K_(1))=(DeltaH)/(2.303R)(1/T_(1)-1/T_(2)) where T_(2) gt T_(1) . Since for an exothermic reaction DeltaH is -ve, it follows that K_(2)/K_(1) lt 1 or K_(2) lt K_(1) .
If the K_(c) of the reaction N_(2)(g)+3H_(2)(g) iff 2NH_(3)(g) at 750 K is 49, then the K_(c) of the reaction NH_(3)(g) iff 1/2N_(2)(g)+3/2H_(2)(g) at the same temperature is
BRILLIANT PUBLICATION-CHEMICAL AND IONIC EQUILIBRIUM-Level - III (Linked Comprehension Type Questions)
