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Consider the following reversible chemical reactions at the same temperature with equilibrium constants K_(1) and K_(2) respectively A_(2)(g)+B_(2)(g) iff 2AB(g) (K_(1)) 6AB(g) iff 3A_(2)(g)+3B_(2)(g)(K_(2)) The relation between K_(1) and K_(2) is
In the matrix A= [[2, 5, 19, -7],[ 35 , -2, 5/2, 12],[ sqrt3, 1, -5 , 17]] Write: (i) The order of the matrix ii) The number of ẹlements iii) Write the elements a_(13), a_(21), a_(33), a_(24),a_(23)
The following equilibria and their equilibrium constants are given N_(2)+3H_(2) iff 2NH_(3)(K_(1)) N_(2)+O_(2) iff 2NO(K_(2)) H_(2)+1/2O_(2) iff H_(2)O(K_(3)) Therefore, the equilibrium constant of the reaction 2NH_(3)+5/2O_(2) iff 2NO+3H_(2)O in terms of K_(1), K_(2) and K_(3) is :
Let a_(1), a_(2), cdots and b_(1), b_(2) cdots be arithmetic progression such that a_(1) = 25, b_(1) = 75 and a_(100) + b_(100) = 100 , then the sum of first hundred terms of the progression a_(1) + b_(1), a_(2) + b_(2), cdots is
BRILLIANT PUBLICATION-CHEMICAL AND IONIC EQUILIBRIUM-Level - III (Linked Comprehension Type Questions)