The following data is known about the melting of `KCl`, `Delta H =7.25 kJ mol ^(-1)`, and `Delta S = 0.007 kJ K ^(-1) mol ^(-1).` Calculate its melting point.

Explanation

`Delta S _("fusion") = ( Delta H _("fusion"))/( T _(f)) or T _(f) = (Delta H _(fus))/( Delta S _(fus))= (7.25 kJ mol ^(-1))/( 0.007 kJ K ^(-1) mol ^(-1)) = 1035.7 K `