The equilibrium constant for the reaction `CO _(2) (g) + H _(2) (g) hArr CO (g) + H _(2) O (g)` at 298 K is 73. Calculate the value of the standard free energy change. `(R=8.314 J mol^(-1) K ^(-1)).`

Explanation

Here, `K = 73 and T = 298 K`
`Delta G ^(@) =- 2. 303 RT log K =- 2. 303 xx 8.314 J mol ^(-1) K ^(-1) xx 298 K xx log 73`
`=-2.303 xx 8.314 J mol ^(-1) K^(-1) xx 298 K xx 1.8633 =- 10632 =- 10.632 kJ mol ^(-1)`