At one atmosphere pressure, ether boils at `35.5^(@)C.` at what temperature will it boil at a pressure of 750 mm Hg, given that heat of vaporisation of ether is 369 `Jmol^(-1)`.

Explanation

`(ln 750mm)/(760 mm) = (369.86 J g ^(-1) xx 74 g mol ^(-1))/(8.314 J K ^(-1) mol ^(-1)) ((T _(2) - 306. 5 K)/(306.5 K))`
`T _(2) = 305.9 K`
`implies k = 2 ba rm ^(-1) implies (p _(2))/( p _(1)) = (d_(2))/(d _(1)) implies d _(2) = d _(1) ((p _(2))/( p _(1)) ) = . 5 xx 5 = 2.5 m`
Also, `- dW = p dV, V = (4)/(3) pi ((d)/(2)) ^(3) = (4)/(3) pi (d ^(3))/(8) = (pi)/(6) d ^(3)`
`implies dV = (pi)/(6) 3d ^(2) d d = (pi)/(2) d ^(2) d d implies - d W = kd xx (pi)/(2) d ^(2) dd = (k)/(2) pi d ^(3) dd `
`implies - W = int - dW = (k)/(2) pi int _(d _(1)) ^( d _(2)) d ^(3) dd = (kpi)/( 2) [ (d ^(4))/( 4)] _(d _(1)) ^(d _(2)) = (kpi)/(8) (d _(2) ^(4) - d _(1) ^(4))`