A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 ml at a consiani temperature of `37.0^(@)C.` As it does so, it absorbs 208 J of heat. The value of qand'w for the process will be `(R =8.31 J mol ^(-1) K) (ln 7.5 = 2.01)` : `q=-208 J, w=-208.J` , `q=-208 J, w=+208 J`, `q=+208 J, w=+208 J`, `q=+208 J, w=-208 J`

Options

A. `q=-208 J, w=-208.J`
B. `q=-208 J, w=+208 J`
C. `q=+208 J, w=+208 J`
D. `q=+208 J, w=-208 J`

Answer

D

Explanation

Process is isothermal reversible expansion, hence `Delta U =0` Therefore, according ot first law of thermodynamics `q =-w . As q = + 208J,` hence ` q =- 208 J.`