For a spontaneous reaction, the `DeltaG`, equilibrium constant `(K)` and `E_("cell") ^(@)` will be, respectively,

Options

A. `- ve, gt 1, + ve `
B. `+ ve gt 1 1, - ve `
C. `- ve, lt 1, - ve `
D. `- ve, gt 1, - ve`

Answer

A

Explanation

According to the relationship between `Delta G, K and E _(cell) ^(@) .` For a spontaneous process `Delta G` has to be negative always, so that `K gt 1` because `Delta G = - 2. 303 RT log K. E _("cell") ^(@)` has to be positive because `Delta G =- n FE ^(@).`