Boron can't form which one of the following anions?
A
`BF_6^(3-)`
B
`BH_4^(-)`
C
`B(OH)_4^(-)`
D
`BO_2^(-)`
Text Solution
Verified by Experts
The correct Answer is:
A
Due to absence of 2d-orbital, maximum covalency is four. Thus, `BF_6^(3-)` is not formed. `BH_4^(-) implies (BH_3+H^(-)), B(OH)_4^(-) implies (B(OH)_3 + OH^(-))` and `BO_2^(-)` are formed.
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