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When NaOH is slowly added to AlCl3 (aq)....

When NaOH is slowly added to `AlCl_3` (aq). It gives a white precipitate which dissolves as more NaOH is added. This is due to

A

the formation of `Al(OH)_3`

B

the formation of sodium aluminate which is soluble

C

the formation of soluble `Al_2O_3`

D

the formation of `Al^(+3)` ion

Text Solution

Verified by Experts

The correct Answer is:
B
This is due to the formation of aluminate ion `AlCl_3 +4NaOH rarr underset("soluble")(Na[Al(OH)_4])+3NaCl`
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