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A metal of atomic mass 60u has a body ce...

A metal of atomic mass 60u has a body centred cubic lattice. The edge length of the unit cell is 286 pm. Calculate the atomic radius and the density of the metal.

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From the given edge length, atomic radius for bcc crystal lattice is determined and density is calculated using the above formula.
Atomic radius for bcc lattice, `r=(sqrt3a)/4=sqrt3/4xx286=123.84"pm"`
For bcc, z = 2 and a = 286 pm = `286xx10^(-10)` cm
Density, `rho=(zxx"atomic mass")/(a^(3)xxN_(A))=(N_(A)="Avogadro.s number")`
= `(2xx60g"mol"^(-1))/((286xx10^(-10))^(3)cm^(3)xx(6.023xx10^(23))mol^(-1))=8.516gcm^(-3)`
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