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Molybdenum (At. wt. = 96g "mol"^(-1)) cr...

Molybdenum (At. wt. = 96g `"mol"^(-1)`) crystallizes as bcc crystal. If density of crystal is 10.3 `g//"cm"^(3)`, then radius of Mo atom is (use `N_(A)=6xx10^(23)`):

A

111 pm

B

314 pm

C

135.96 pm

D

216.35

Text Solution

Verified by Experts

The correct Answer is:
C
Use `a^(3)=z/rho(M/N_(A))," "a=314"pm "r=(sqrt3a)/4rArr135.96"pm"`
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