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How many unit cells are present in 39 g ...

How many unit cells are present in 39 g of potassium that crystallises in body-centred cubic structure?

A

`N_(A)`

B

`N_(A)/4`

C

`0.5N_(A)`

D

`0.75N_(A)`

Text Solution

Verified by Experts

The correct Answer is:
C
Number of atoms = `("Mass")/("Atomic mass")xxN_(A)=39/39xxN_(A)=N_(A)`
In bcc unit cell, Z = 2
`therefore` Number of unit cells = `N_(A)/2=0.5N_(A)`
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