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The specific conductivity of 0.1 M solut...

The specific conductivity of 0.1 M solution of a weak acid at 298 K is 0.00159 `"ohm^(-1) cm^(-1)` . Calculate the degree of dissociation of the acid if its molar conductance at infinite dilution is 350.5 `"ohm"^(-1) cm^(2) mol^(-1)` .

Text Solution

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Specific conducitivity `k\0.00519 ohm^(-1) cm^(-1)`
Molar conducitivity `wedge_(m)^(@)=(k)/(C )=(0.0519 ohm^(-1) cm^(-1))/(10^(-4) cm mol)=15.9 ohm^(-1) cm^(2) mol^(-1)`
`therefore` Degree of dissociation =4.54 %
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