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The specific conductivity of the saturat...

The specific conductivity of the saturated aqueous solution of AgCl is `1.82xx10^(-6) ohm^(-1) cm^(-1)` at 298K. Calculate me solubility of AgCl.`[wedge_(m)^(@)(Ag^(+))=61.83 ohm^(-1) cm^(2) mol^(-1)]` and `wedge_(m)^(@) (CI)^(-)=76.41 ohm^(-1) cm^(2) mol^(-1)`

Text Solution

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`wedge_(m)^(@)(AgCI)=lambda_(m)^(@)(Ag^(+))+lambda_(m)^(@)(CI)^(-)`
specific conducitivity =`1.82 xx10^(4) ohm^(-1) cm^(-1)`
solubility =`(k xx 1000 cm^(3) l^(-1))/(wedge_(m)^(@))=(1.82 xx10^(-6) ohm^(-1) cm^(-1) xx 1000 cm^(3) l^(-1))/(138.24 ohm^(-1) cm^(2) mol^(-1))=1.32 xx120^(-5) mol L^(-1)`
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