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The E at 25^(@) C for the following reac...

The E at `25^(@)` C for the following reaction is 0.22 V. The equilibrium constant at `25^(@)` C is very `H_(2)(g) +2AgCl(s) rarr -2Ag (s)+2HCl(aq)`

A

`2.8 xx 10^(7)`

B

`5.2 xx 10^(8)`

C

`5.2 xx10^(6)`

D

`5.2 xx10^(3)`

Text Solution

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The correct Answer is:
C

`E^(@)=(0.0591)/(2) log K_(eq), log k_(eq)=(2xx0.22)/(0.591) rarr 7.44 or k_(eq)=2.8 xx10^(7)`
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