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Using the following E^(@) values for ele...

Using the following `E^(@)` values for electrode potentials, calculate `triangle G^(@)` in kJ for the indicated reaction: `5Ce^(4+) (aq) + Mn^(2+) (aq) + 4H_(2)O(l) rarr 5Ce^(3+) (aq) + MnO_(4)^(-) (aq) +8H^(+) (aq)`
`MnO_(4)^(-) (aq) +8H^(+) (aq) +5e^(-) rarr Mn^(2+) (aq) + 4H_(2) O(l), E^(@) = +1.51V`
`Ce^(4+) (aq) + e^(-)rarr Ce^(3+)(aq), E^(@) = +1.61V`

A

`-9.65`

B

`-24.3`

C

`-48.25`

D

`-35.2`

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(cell)^(@)=E_(RP(RHS))^(@)-E_(RP(LHS))^(@)=1.61 -1.51 rarr 0.10 v`
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