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The equilibrium constant of acetic acid ...

The equilibrium constant of acetic acid in an aqueous solution of concentration c is given by

A

`K=(cwedge_(c )^(2))/(wedge^(infty)+wedge_(c ))`

B

`K=(cwedge_(c )^(2))/(wedge^(infty)(wedge^(infty)-wedge_(c )))`

C

`K=(cwedge_(c )^(2))/(wedge^(infty)+wedge_(c ))`

D

`K=(cwedge_(c )^(2))/(wedge^(infty)(wedge^(infty)+wedge_(c )))`

Text Solution

Verified by Experts

The correct Answer is:
C

`CH_(3)COOH rarr CH_(3)COO+H^(+)k=(calpha^(2))/(1-alpha)`
since `alpha=wedge_(c )//wedge^(infty)` we get =`(c(wedge_(c ))//wedge^(infty)^(2))/(wedge^(infty(wedge^(infty))//wedge_(c ))`
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