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Electrolysis of dilute aqueous NaCl solu...

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mole of `H_(2)` gas at the cathode is:

A

`9.65 xx 10^(4)` sec

B

`19.3 xx 10^(4)` sec

C

`28.95 xx 10^(4)` sec

D

`38.6 xx 10^(4)` sec

Text Solution

Verified by Experts

The correct Answer is:
A
Mass of 0.01 mol `H_(2) =0.02 g w=(ltE)/(96500),0.02t=19.3 xx10^(4) sec`
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