The sum of coordination number and oxidation number of the metal M in the complex `[M(en)_2 (C_2O_4)]Cl` (where en is ethylenediamine) is:

Options

A. 7
B. 8
C. 9
D. 6

Answer

C

Explanation

`[M(en)_2(C_2O_4)]^(+)`. If oxidation number of M is x, then `x + 0 + (-2) = +1 or x=+3`.
As en and `C_2O_4` are bidentate ligands, coordination number = 6.
`therefore` Sum of oxidation number and coordination number=3+6=9.