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Hybridisation, shape and magnetic moment...

Hybridisation, shape and magnetic moment of K₃[Co(CO)₆] is

A

`d^3 sp^3`, octahedral 4.9 BM

B

`sp^3 d^2`, octahedral, 4.9 B.M.

C

`dsp^2` square planar, 4.9B.M.

D

`sp^3`, tetrahedral, 4.9 B.M.

Text Solution

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The correct Answer is:
B
In each case, magnetic moment is 4.9 B.M. which shows that each of them has 4 unpaired electrons. Further, in the given complex, oxidation state of cobalt is +3. Hence, it will have 3do configuration,ie,

Thus, hybridisation possible is `sp^3 d^2`, ie, outer orbital (high spin) octahedral complex:
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