The correct order of magnetic moments (spin only values in B.M.) among is

Options

A. `[MnCl_4]^(2-) gt [CoCl_4]^(2-) gt [Fe(CN)_6]^(4-)`
B. `[Fe(CN)_6]^(4-) gt [CoCl_4]^(2-) gt [MnCl_4]^(2-)`
C. `[Fe(CN)_6]^(4-) gt [MnCl_4]^(2-) gt [CoCl_4]^(2-)`
D. `[MnCl_4]^(2-) gt [Fe(CN)_6]^(4-) gt [CoCl_4]^(2-)`

Answer

A

Explanation

The order is `[MnCl_4]^(2-) gt [CoCl_4]^(2-) gt [Fe(CN)_6]^(4-)`
In `[MnCl_4]^(2-)`, outer orbitals undergo hybridisation. In `[CoCl_4]^(2-)` , 3d orbitals not participating in hybridisation. In `[Fe(CN)_6]^(4-)`, inner orbital complex is formed and is diamagnetics.