Home
Class 11
PHYSICS
There is a soap bubble of radius 2.4xx10...

There is a soap bubble of radius `2.4xx10^(-4)m` in air cylinder which is originally at a pressure of `10^(5)(N)/(m^(2))`. The air in the cylinder is now compressed isothermally until the radius of the bubble is halved. (the surface tension of the soap film is `0.08Nm^(-1))`. The pressure of air in the cylinder is found to be `8.08xx10^(n)(N)/(m^(2))`. What is the value of n?

Text Solution

Verified by Experts

The correct Answer is:
`8.08xx10^(5)N//m^(2)`
Promotional Banner

Topper's Solved these Questions

  • ELASTICITY, SURFACE TENSION AND FLUID MECHANICS

    ALLEN |Exercise Exercise 4 A (Fluid Statics)|13 Videos

  • ELASTICITY, SURFACE TENSION AND FLUID MECHANICS

    ALLEN |Exercise Exercise 4 A (Fuild Dynamics)|7 Videos

  • ELASTICITY, SURFACE TENSION AND FLUID MECHANICS

    ALLEN |Exercise Exercise 4 A (Elasticity)|7 Videos

  • CENTRE OF MASS

    ALLEN |Exercise EXERCISE-V B|19 Videos

  • ERROR AND MEASUREMENT

    ALLEN |Exercise Part-2(Exercise-2)(B)|22 Videos

Similar Questions

Explore conceptually related problems

There is a soap bubble of radius 2.4 xx 10^(-4)m in air cylinder at a pressure of 10^(5) N//m^(2) . The air in the cylinder is compressed isothermal until the radius of the bubble is halved. Calculate the new pressure of air in the cylinder. Surface tension of soap solution is 0.08 Nm^(-1) .

A container filled with air under pressure P_(0) contains a soap bubble of radius R the air pressure has been reduced to half isothermally and the new radius of the bubble becomes (5R)/(4) if the surface tension of the soap water solution. Is S, P_(0) is found to be (12nS)/(R) . Find the value of n.

A soap film in formed on a frame of area 4xx10^(-3)m^(2) . If the area of the film in reduced to half, then the change in the potential energy of the film is (surface tension of soap solution =40xx10^(-3)N//m)

The surface tension of soap solution is 0.03 N//m . The work done in blowing to from a soap bublle of surface area 40 cm^(2) , (in J) , is

Find the difference of air pressure (in N-m^(-2) ) between the inside and outside of a soap bubble 5 mm in diameter, if the surface tension is 1.6 N-m^(-1) :-

Curved surface area of a right circular cylinder is 4.4 m^(2) . If the radius of the base of the cylinder is 0.7 m, find its height.

The work done in increasing the size of soap film with dimensions 8cm xx3.75cm to 10cmxx6cm is 2xx10^(-4)J . The surface tension of the film in (N)/(m) is

How much should the pressure on a litre of water be changed to compress it by 0.10 % ? (B=2.2 xx 10 ^(9) N//m^(2))