A satellite close to the earth is in orbit above the equator with a period of rotation of `1.5` hours. If it is above a point `P` on the equtor at some time, it will be above `P` again after time ...........

Answer

1.6 hours if it is rotating from west to east `(24)/(17)` hours if it is rotating east to west

Explanation

Relative velocity when satellite revolving anticlockwise
`(omega_(1)+omega_(2))t=2piimplies((4pi)/(3)+(2pi)/(24))t=2pi,t=(24)/(17)`
if it moves in same direction
`((4pi)/(3)-(2pi)/(24))t=2pi`
`((30pi)/(24))t=2pi impliest=(24)/(15)=1.6hrs`