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An electromagnetic wave of wavelength la...


An electromagnetic wave of wavelength `lamda_(0)` (in vacuum) passes from P towards Q crossing three difference media of refractive index `mu,2mu` and `3mu` respectively as shown in figure `phi_(P)` and `phi_(Q)` be the phase of the wave at points P and Q. Find the phase difference `phi_(Q)-phi_(P)`. [take `mu=1`]

A

0

B

`(pi)/(4)`

C

`(pi)/(2)`

D

`pi`

Text Solution

Verified by Experts

The correct Answer is:
C
Optical path difference between (OPD) P & Q
(O.P.D) `=2.25lamda_(0)xx1+(3.5lamda_(0))xx2+3lamda_(0)xx3=18.25lamda_(0)` and phase difference `Deltaphi=(2pi)/(lamda_(0))xxDeltax=(pi)/(2)`
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