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Two slits at a distance of 1mm are illum...

Two slits at a distance of `1mm` are illuminated by a light of wavelength `6.5xx10^-7m`. The interference fringes are observed on a screen placed at a distance of `1m`. The distance between third dark fringe and fifth bright fringe will be

A

0.65 mm

B

1.625 mm

C

3.25 mm

D

0.975 mm

Text Solution

Verified by Experts

The correct Answer is:
B
Distance between third dark fringe and the fifth bright fringe.
`=2.5beta=2.5(lamdaD)/(d)=2.5(6.5xx10^(-7)xx1)/(10^(-3))=1.625mm`
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Knowledge Check

  • In Young's experiment distance between 5^(th) dark fringe and 3rd bright fringe is x_(5 )-x_(3)=......x

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    2
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    3
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